The calculate the resultant force, we always just need to add up the vectors. In this question we just need to find the magnitude, which we can do using the pyhtagorean theorem, so \(\sqrt{4^2 + 3^2} = 5 \).
CloseSince the ball is moving up, it must experience a net force that is pointing up. The only 2 forces that act on it in this question are the weight and the bouyant force, the bouyant force being the one pointing upwards. The bouyant force, by definition, is the weight of the displaced liquid, which must be larger than the weight of the ball, otherwise there would be no net force pointing upwards.
CloseThis is again a simple, yet really important definition to remember. Momentum is always conserved (in an isolated system).
CloseCorrect Answer: B
In a free body diagram it is key to remember that we do not label the components of the forces, only the forces themselves, so C and D are surely wrong. Now between A and B. It is important to understand that the centripetal force is not an actual force, it is simple a concept that was created to label all the forces that act towards the center of a circle. Hence in this case the x component of the tension is acting towards the center if the circle, so that will be called the centripetal force, but this force does not just exist on its own. So its B.
CloseThe formula is \( \Delta p = m \cdot \Delta v \). In this question, our ball rebounds, meaning its velocity changes direction, so if we take speed to the right as positive, then speed to the left will be negative, so our final speed will be \( -5 \). So our change in speed is \( 5 - (-5) = 10 \), multiplied by our mass which is \( 1 \), gives \( C \).
CloseWe know that the persons weight is \(W=mg=80\cdot 9.81 = 784N\). So the net force on the person is \(N-mg=ma\) so \(N=m(g+a)=80(9.81+2)=\text{944}{N}\).
CloseIf a body is in translational equilibrium then the sum of the forces must be 0, and for that to be possible they cannot be in the same direction.
CloseAccording to Newton's 3rd law the force pairs must have the same origin/type. So the pair of a gravitational force must be another gravitational force.
CloseThe impulse received is equal to the change in momentum. So \( mv_1 - mv_2 \).
CloseThe net force is defined as the rate of change of momentum, \( F_{net} = \frac{\Delta p}{\Delta t} \), in other words, the slope of the momentum-time graph, which here is 2.
CloseWe know for sure that momentum is conserved as there are no external forces. Considering that velocity is a vector, the momentum before the collision is \( 2mv - 2mv = 0 \), so after the collision it must remain 0.
CloseThe only force present in this interaction is the gravitational force, and since we have circular motion and this gravitational force points to the center of the circle, at the same time it is the centripetal force.
CloseVelocity is a VECTOR, which has a direction associated with it, and the direction is constantly changing since the satellite is moving in a circle.
Close