The sum of the first three positive integers is 6.

Detailed Answer

        
import java.util.Scanner;

public class Loops {
    public static void main(String[] args) {
        int sum = 0;
        
        for (int i = 1; i <= 3; i++) {
            sum = sum + i;
        }
        
        System.out.println("The sum of the first three positive integers is " + sum + ".");
    }
}
        
    

The product of the first five positive integers is 120.

Detailed Answer

        
public class Loops {
    public static void main(String[] args) {
        int product = 1;
        
        for (int i = 1; i <= 5; i++) {
            product *= i;
        }
        
        System.out.println("The product of the first five positive integers is " + product + ".");
    }
}
        
    

Assuming the user inputs the number 7, the output should be:

7 x 1 = 7

7 x 2 = 14

7 x 3 = 21

7 x 4 = 28

7 x 5 = 35

7 x 6 = 42

7 x 7 = 49

7 x 8 = 56

7 x 9 = 63

7 x 10 = 70

Detailed Answer

        
import java.util.Scanner;

public class Loops {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        
        System.out.print("Enter a positive integer: ");
        int number = scanner.nextInt();
        
        for (int i = 1; i <= 10; i++) {
            System.out.println(number + " x " + i + " = " + (number * i));
        }
    }
}
        
    

Assuming the user inputs the number 6, the output should be:

The sum of all even numbers from 1 to 6 is 12.

Detailed Answer

        
import java.util.Scanner;

public class Loops {

    public static void main(String[] args) {
        
        Scanner scanner = new Scanner(System.in);
        
        System.out.print("Enter a positive integer:");
        int number = scanner.nextInt();
        
        int sum = 0;
        
        
        if (number < 1) {
            System.out.println("Please insert a positive integer");
        }
        
        else {
            for (int i = 2; i <= number; i+=2) {
                sum = sum + i;
            }
        }
        
        System.out.println("The sum of all even number from 1 to " + number + " is " + sum);
    }
}
            
        
    

Assuming the user inputs the number 5, the output should be:

5
4
3
2
1

Detailed Answer

        
import java.util.Scanner;

public class Loops {

    public static void main(String[] args) {
        
        Scanner scanner = new Scanner(System.in);
        
        System.out.print("Enter a positive integer:");
        int number = scanner.nextInt();
        
        if (number < 1) {
            System.out.println("Please insert a positive integer.");
        }
        
        else {
            for (int i = number; i >= 1; i--) {
                System.out.println(i);
            }
        }

    }
}
            
        
    

Assuming the user inputs the number 28, the output should be:

The number 28 is a perfect number.

Detailed Answer

                
import java.util.Scanner;

public class Loops {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        
        System.out.print("Enter a positive integer between 1 and 500: ");
        int number = scanner.nextInt();
        int sumOfDivisors = 0;
        
        
        if (number < 1 || number > 500) {
            System.out.println("Please insert a valid integer");
        }
        
        else {
            for (int i = 1; i < number; i++) {
                if (number % i == 0) {
                    sumOfDivisors = sumOfDivisors + i;
                    
                }
                
            }
            
            if (sumOfDivisors == number) {
                System.out.println("The number " + number + " is a perfect number"); 
            }
            
            else {
                System.out.println("The number " + number + " is a not perfect number"); 
            }
            
        }


    }
    
}
                
            

Assuming the base is 2 and the exponent is 3, the output should be:

2 raised to the power of 3 equals 8.

Detailed Answer

                
import java.util.Scanner;

public class Loops {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        
        System.out.print("Enter a base number: ");
        int base = scanner.nextInt();
        
        System.out.print("Enter an exponent: ");
        int exponent = scanner.nextInt();
        
        int result = 1;
        
        for (int i = 1; i<= exponent; i++) {
            result = result * base;
        }
        
        System.out.println(base + " raised to the power of " + exponent + " equals " + result);

    }
}
                       
                
            

Assuming the user inputs the numbers 5, 10, 15, and then -1 to stop, the output should be:

The total sum of the positive numbers entered is 30.

Detailed Answer

        
import java.util.Scanner;

public class Loops {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        
        int sum = 0;
        System.out.println("Enter a positive integer to sum up. Enter a negative integer to stop.");
        
        while (true) {
            
            System.out.print("Enter a number: ");
            int number = scanner.nextInt();
            
            if (number < 0) {
                break;
            }
    
            else {
                sum = sum + number;
            }
        }

        System.out.println("The total sum of the positive integers entered is " + sum);

    }
}
               
        
    

Assuming the user inputs the numbers 5, 7, 8, 4, 2, and then 0 to stop, the output should be:

The count of all even integers from this set of numbers is 3.

Detailed Answer

        
import java.util.Scanner;

public class Loops {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
        
        System.out.println("Enter a series of integers. Input 0 to stop.");
        int count = 0;
        
        while (true) {
            
            System.out.print("Enter an integer: ");
            int number = scanner.nextInt();
            
            if (number == 0) {
                break;
            }
            
            else if (number % 2 == 0) {
                count = count + 1;
            }
        }

        System.out.println("The count of all even integers from this set of numbers is " + count);

    }
}
               
        
    

Assuming the user inputs the numbers 3, 5, 7, 2, 8, 5, and then -2 to stop, the output should be:

The average of all odd numbers from this set is 5.

Detailed Answer

        
import java.util.Scanner;

public class Loops {
    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
    
        System.out.println("Enter positive integers. Enter a negative integer to stop.");
        int sum = 0;
        int count = 0;
        
        while (true) {
            
            System.out.print("Enter an integer: ");
            int number = scanner.nextInt();
            
            if (number < 0) {
                break;
            }
            
            else if (number % 2 != 0) {
                sum = sum + number;
                count = count + 1;
            } 
        }
        
        if (count > 0) {
            double average = (double) sum / count;
            System.out.println("The average of all odd numbers from this set is " + average);
        }
        
        else {
            System.out.println("No odd numbers were entered");
        } 
    }
}