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Schedule a call :) CloseThe optimal temperature for an enzyme is the temperature at which it has the highest activity and catalyzes the reaction most efficiently. This can be determined by finding the temperature that produces the most product in a given time. In this case, the enzyme has the highest activity at 30°C, as it produces 6 mg of product in 10 minutes.
CloseBoth Krebs cycle and Calvin cycle are examples of metabolic pathways that involve a cycle of enzyme-catalyzed reactions, where each product is used as a substrate for another reaction and one product is regenerated to start another cycle.
CloseThe graph shows the rate of reaction on the y-axis and substrate concentration on the x-axis. The curve labeled “Uninhibited” shows the rate of reaction without any inhibitor, while the curve labeled “B” shows the rate of reaction with a competitive inhibitor. A competitive inhibitor is a molecule that competes with the substrate for binding to the active site of the enzyme. This reduces the number of available active sites and thus decreases the rate of reaction. However, this effect can be overcome by increasing the substrate concentration, as shown by the curve for “B” approaching the curve for “Uninhibited” at high substrate concentrations.
CloseLowering the activation energy of a reaction means that less energy is required for the reactants to reach the transition state and form products. This increases the proportion of reactant molecules that have enough energy to react and thus increases the rate of the reaction.
CloseThe accumulation of product X inhibits the enzyme 1 through negative feedback mechanism hence reducing the rate of the reaction and preventing the wasteful use of resources.
CloseTemperature (°C) | Product Formed (mg) |
---|---|
10 | 2 |
20 | 4 |
30 | 6 |
40 | 5 |
50 | 3 |